mysql_prepare doesn't return an error
| Bug #33090 | mysql_prepare doesn't return an error | ||||
|---|---|---|---|---|---|
| Submitted: | 2005-05-21 10:37 UTC | Modified: | 2005-05-21 11:36 UTC | ||
| From: | georg@php.net | Assigned: | georg (profile) | ||
| Status: | Closed | Package: | MySQLi related | ||
| PHP Version: | 5.0.4 | OS: | all | ||
| Private report: | No | CVE-ID: | None | ||
[2005-05-21 10:37 UTC] georg@php.net
Description:
------------
In later versions of libmysqlclient 4.1 and 5.0 the api
call mysql_stmt_close also clears mysql->net.error*
values.
This affects that mysql_prepare doesn't return an error
with current version of libmysql.
Reproduce code:
---------------
<?php
$mysql = new mysqli("localhost", "user", "password", "test");
if (!($stmt = $mysql->prepare("this will never work"))) {
printf("Error: %s\n", $mysql->error);
}
$mysql->close();
?>
Expected result:
----------------
Error: You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for
the right syntax to use near 'this will never work' at
line 1
Actual result:
--------------
Error:
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[2005-05-21 11:36 UTC] andrey@php.net