PHP :: Bug #43533 :: escapeshellarg('') returns null

Bug #43533

escapeshellarg('') returns null

Submitted:

2007-12-08 02:58 UTC

Modified:

2007-12-09 16:37 UTC

Votes:	1
Avg. Score:	4.0 ± 0.0
Reproduced:	0 of 1 (0.0%)

From:

josephk at etelos dot com

Assigned:

Status:

Closed

Package:

*Directory/Filesystem functions

PHP Version:

5.2.5

OS:

Cent OS 5

Private report:

CVE-ID:

None

[2007-12-08 02:58 UTC] josephk at etelos dot com

Description:
------------
escapeshellarg() returns null when passed an empty string instead of returning an empty string.  The documentation doesn't say anything about giving a return value of null.

Reproduce code:
---------------
<?php
var_dump(escapeshellarg(''));
?>

Expected result:
----------------
string ''

Actual result:
--------------
null

Patches

Pull Requests

History

AllCommentsChangesGit/SVN commitsRelated reports

[2007-12-08 10:59 UTC] felipe@php.net

In PHP 5.3.0-dev (cli) (built: Dec  7 2007 22:22:09) it shows:
string(2) "''"

[2007-12-09 04:30 UTC] crrodriguez at suse dot de

5_2 returns NULL (wrong value) , for some reason 5_3 is right.

[2007-12-09 16:37 UTC] iliaa@php.net

This bug has been fixed in CVS.

Snapshots of the sources are packaged every three hours; this change
will be in the next snapshot. You can grab the snapshot at
http://snaps.php.net/.
 
Thank you for the report, and for helping us make PHP better.