Java Program to Find Smallest Number in an Array

This article is created to cover a program in Java that find and prints the smallest number in an array of n numbers or elements, entered by user at run-time.

Java Find Smallest Number in Array using for Loop

The question is, write a Java program to find the smallest number in an array of n numbers. The program given below is its answer:

import java.util.Scanner;

public class CodesCracker
{
   public static void main(String[] args)
   {
      int tot, i, small;
      Scanner scan = new Scanner(System.in);
      
      System.out.print("Enter the Size of Array: ");
      tot = scan.nextInt();
      int[] arr = new int[tot];
      System.out.print("Enter " +tot+ " Numbers: ");
      for(i=0; i<tot; i++)
         arr[i] = scan.nextInt();
      
      small = arr[0];
      for(i=1; i<tot; i++)
      {
         if(small>arr[i])
            small = arr[i];
      }
      
      System.out.println("\nSmallest Number = " +small);
   }
}

The snapshot given below shows the sample run of above program with user input 6 as size and 20, 21, 22, 17, 18, 19 as six numbers, to find and print the smallest number among these:

java find smallest number in array

Java Find Smallest Number in Array using while Loop

To create the same program using while loop, instead of for. Then replace the following block of code, from above program:

for(i=1; i<tot; i++)
{
   if(small>arr[i])
      small = arr[i];
}

with the block of code given below:

i = 0;
while(i<tot)
{
   if(small>arr[i])
      small = arr[i];
   i++;
}

Same Program in Other Languages

Java Online Test

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