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std::chrono::year::operator+=, std::chrono::year::operator-= - cppreference.com

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constexpr std::chrono::year& operator+=( const std::chrono::years& y ) noexcept;

 (1) (since C++20)

constexpr std::chrono::year& operator-=( const std::chrono::years& y ) noexcept;

 (2) (since C++20)

Adds or subtracts y.count() years from the year value.

1) Equivalent to *this = *this + y;.

2) Equivalent to *this = *this - y;.

Return value

A reference to this year after modification.

Notes

If the result would be outside the range [-32767, 32767], the actual stored value is unspecified.

Example

#include <chrono>
#include <iostream>

int main()
{
    using namespace std::literals::chrono_literals;
    std::cout << std::boolalpha;

    std::chrono::year y{2020};
 
    y += std::chrono::years(12);
    std::cout << (y == 2032y) << ' ';

    y -= std::chrono::years(33);
    std::cout << (y == 1999y) << '\n';
}

Output:

See also