operator+(std::move_iterator)

operator+(std::move_iterator) - cppreference.com

From cppreference.com

Defined in header `<iterator>`
`template< class Iter > move_iterator<Iter> operator+ ( typename move_iterator<Iter>::difference_type n, const move_iterator<Iter>& it );`		(since C++11) (constexpr since C++17) (until C++20)
`template< class Iter > constexpr move_iterator<Iter> operator+ ( std::iter_difference_t<Iter> n, const move_iterator<Iter>& it );`		(since C++20)

Returns the iterator it incremented by n.

This overload participates in overload resolution only if it.base() + n is well-formed and has type Iter.

(since C++20)

n	-	the number of positions to increment the iterator
it	-	the iterator adaptor to increment

it + n

The following behavior-changing defect reports were applied retroactively to previously published C++ standards.

DR	Applied to	Behavior as published	Correct behavior
LWG 3293	C++20	the non-member `operator+` was constrained to require `it + n` is well-formed and has type `Iter`	changed to `it.base() + n`