std::unique_ptr<T,Deleter>::operator*, std::unique_ptr<T,Deleter>::operator-> - cppreference.com
From cppreference.com
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(1) | (since C++11) (constexpr since C++23) |
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(2) | (since C++11) (constexpr since C++23) |
operator* and operator-> provide access to the object owned by *this.
These member functions are only provided for unique_ptr for the single objects i.e. the primary template.
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1) If |
(since C++23) |
If get() is a null pointer, the behavior is undefined.
Return value
1) Returns the object owned by *this, equivalent to *get().
2) Returns a pointer to the object owned by *this, i.e. get().
Exceptions
1) May throw if pointer has a throwing operator*.
Notes
The use of std::add_lvalue_reference is to make it possible to instantiate std::unique_ptr<void> since void& isn't allowed in C++ while std::add_lvalue_reference<void> produces void. See LWG673 for details.
Example
#include <iostream> #include <memory> struct Foo { void bar() { std::cout << "Foo::bar\n"; } }; void f(const Foo&) { std::cout << "f(const Foo&)\n"; } int main() { std::unique_ptr<Foo> ptr(new Foo); ptr->bar(); f(*ptr); }
Output:
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
| DR | Applied to | Behavior as published | Correct behavior |
|---|---|---|---|
| LWG 2762 | C++11 | operator* might be potentially-throwingeven if *get() was noexcept
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added a conditional exception specification |
| LWG 4148 | C++23 | operator* could return a dangling reference ifelement_type* differs from Deleter::pointer
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the program is ill- formed in this case |
See also
| returns a pointer to the managed object (public member function) [edit] |