std::is_standard_layout - cppreference.com
From cppreference.com
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(since C++11) | |
std::is_standard_layout is a UnaryTypeTrait.
If T is a standard-layout type, provides the member constant value equal to true. For any other type, value is false.
If std::remove_all_extents_t<T> is an incomplete type and not (possibly cv-qualified) void, the behavior is undefined.
If the program adds specializations for std::is_standard_layout or std::is_standard_layout_v, the behavior is undefined.
Template parameters
Helper variable template
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(since C++17) | |
Inherited from std::integral_constant
Member constants
true if T is a standard-layout type, false otherwise (public static member constant) |
Member functions
converts the object to bool, returns value (public member function) | |
returns value (public member function) |
Member types
| Type | Definition |
value_type
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bool
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type
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std::integral_constant<bool, value>
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Notes
A pointer to a standard-layout class may be converted (with reinterpret_cast) to a pointer to its first non-static data member (see empty base optimization) and vice versa.
If a standard-layout union holds two or more standard-layout structs, it is permitted to inspect the common initial part of them.
The macro offsetof is only guaranteed to be usable with standard-layout classes.
Example
#include <type_traits> struct A { int m; }; static_assert(std::is_standard_layout_v<A> == true); class B: public A { int m; }; static_assert(std::is_standard_layout_v<B> == false); struct C { virtual void foo(); }; static_assert(std::is_standard_layout_v<C> == false); int main() {}
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
| DR | Applied to | Behavior as published | Correct behavior |
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| LWG 2015 | C++11 | T could be an array of incompleteclass type with unknown bound |
the behavior is undefined in this case |