std::remove_cv, std::remove_const, std::remove_volatile - cppreference.com
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(1) | (since C++11) |
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(2) | (since C++11) |
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(3) | (since C++11) |
Provides the member typedef type which is the same as T, except that its topmost cv-qualifiers are removed.
1) Removes the topmost const, or the topmost volatile, or both, if present.
2) Removes the topmost const.
3) Removes the topmost volatile.
If the program adds specializations for any of the templates described on this page, the behavior is undefined.
Member types
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type
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the type T without cv-qualifier
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Helper types
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(since C++14) | |
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Possible implementation
template<class T> struct remove_cv { typedef T type; }; template<class T> struct remove_cv<const T> { typedef T type; }; template<class T> struct remove_cv<volatile T> { typedef T type; }; template<class T> struct remove_cv<const volatile T> { typedef T type; }; template<class T> struct remove_const { typedef T type; }; template<class T> struct remove_const<const T> { typedef T type; }; template<class T> struct remove_volatile { typedef T type; }; template<class T> struct remove_volatile<volatile T> { typedef T type; };
Example
Removing const/volatile from const volatile int* does not modify the type, because the pointer itself is neither const nor volatile.
#include <type_traits> template<typename U, typename V> constexpr bool same = std::is_same_v<U, V>; static_assert ( same<std::remove_cv_t<int>, int> && same<std::remove_cv_t<const int>, int> && same<std::remove_cv_t<volatile int>, int> && same<std::remove_cv_t<const volatile int>, int> && // remove_cv only works on types, not on pointers not same<std::remove_cv_t<const volatile int*>, int*> && same<std::remove_cv_t<const volatile int*>, const volatile int*> && same<std::remove_cv_t<const int* volatile>, const int*> && same<std::remove_cv_t<int* const volatile>, int*> ); int main() {}