std::compare_strong_order_fallback - cppreference.com
From cppreference.com
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Performs three-way comparison on subexpressions t and u and produces a result of type std::strong_ordering, even if the operator <=> is unavailable.
If std::decay_t<T> and std::decay_t<U> are the same type, std::compare_strong_order_fallback(t, u) is expression-equivalent to:
std::strong_order(t, u), if it is a well-formed expression;- otherwise,
t == u ? std::strong_ordering::equal :t < u ? std::strong_ordering::less :std::strong_ordering::greater
- if the expressions
t == uandt < uare both well-formed and each ofdecltype(t == u)anddecltype(t < u)models boolean-testable, except thattanduare evaluated only once.
In all other cases, std::compare_strong_order_fallback(t, u) is ill-formed, which can result in substitution failure when it appears in the immediate context of a template instantiation.
Customization point objects
The name std::compare_strong_order_fallback denotes a customization point object, which is a const function object of a literal semiregular class type. See CustomizationPointObject for details.
Example
Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
| DR | Applied to | Behavior as published | Correct behavior |
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| LWG 2114 (P2167R3) |
C++20 | the fallback mechanism only required return types to be convertible to bool
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constraints strengthened |
See also
performs 3-way comparison and produces a result of type std::strong_ordering(customization point object)[edit] |