Super Binding

A dotted lookup such as ``super(A, a).x`` searches

``obj.__class__.__mro__`` for a base class ``B`` following ``A`` and then

``a.__class__.__mro__`` for a base class ``B`` following ``A`` and then

returns ``B.__dict__['x'].__get__(a, A)``. If not a descriptor, ``x`` is

returned unchanged.

x = 999

def m(self):

'Demonstrate these two calls are equivalent'

result1 = super(A, a).x

result2 = B.__dict__['x'].__get__(a, A)

'Demonstrate these two descriptor invocations are equivalent'

result1 = super(A, self).x

result2 = B.__dict__['x'].__get__(self, A)

return result1 == result2

.. doctest::

:hide:

>>> a = A()

>>> a.__class__.__mro__.index(B) > a.__class__.__mro__.index(A)

True

>>> super(A, a).x == B.__dict__['x'].__get__(a, A)

True

>>> a.m()

True