Infer union from conditional definition in if statement
Maybe if a variable is initialized both in if and else blocks, the resulting type should be the union of the types of the initializers (only when using --allow-redefinitions):
if foo(): x = 0 # Type of x is 'int' here else: x = '' # No error here # Type of x is 'str' here reveal_type(x) # Union[int, str]
Currently the second assignment generates an error, and the type of x is int everywhere.
This is a generalization of #6232 and related to #1174 (but not a direct follow-up issue).