[Python-Dev] any support for a methodcaller HOF?
Eric Nieuwland
eric.nieuwland at xs4all.nl
Sat Feb 4 03:48:18 CET 2006
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Sat Feb 4 03:48:18 CET 2006
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On 4 feb 2006, at 3:18, Nick Coghlan wrote: > All I'm suggesting is that a similarly inspired syntax is worth > considering when it comes to deferred expressions: > > def f(x): > return x*x > > => f = (x*x def (x)) It's not the same, as x remains free whereas in g = [x*x for x in seq] x is bound. Yours is f = lambda x: x*x and it will die by Guido hand... --eric
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