[Python-Dev] hex() and oct() still include the trailing L

[Python-Dev] hex() and oct() still include the trailing L - change this in 2.6?

Gregory P. Smith greg at krypto.org
Fri Nov 9 03:05:25 CET 2007

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I thought the hell of stripping trailing Ls off of stringed numbers was gone
but it appears that the hex() and oct() builtins still leave the trailing
'L' on longs:

Python 2.6a0 (trunk:58846M, Nov  4 2007, 15:44:12)
[GCC 4.1.2 (Ubuntu 4.1.2-0ubuntu4)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> x = 0xffffffffc10025be
>>> x
18446744072652596670L
>>> str(x)
'18446744072652596670'
>>> hex(x)
'0xffffffffc10025beL'
>>> '0x%x' % (x)
'0xffffffffc10025be'
>>> oct(x)
'01777777777770100022676L'

This appears to be fixed in py3k (as there is no longer an int/long to
distinguish).  Can we at least get rid of the annoying L in 2.6?

-gps
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