[Python-Dev] can't assign to function call
Serhiy Storchaka
storchaka at gmail.com
Mon Mar 18 18:25:02 CET 2013
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Mon Mar 18 18:25:02 CET 2013
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On 18.03.13 17:40, Steven D'Aprano wrote: > On 19/03/13 02:01, Hrvoje Niksic wrote: >> Assigning to function calls is orthogonal to reference types. For >> example, Python manages assignment to subscripts without having >> references just fine: >> >> val = obj[index] # val = obj.__getitem__(index) >> obj[index] = val # obj.__setitem__(index, val) >> >> In analogy with that, Python could implement what looks like >> assignment to function call like this: >> >> val = f(arg) # val = f.__call__(arg) >> f(arg) = val # f.__setcall__(arg, val) > > That's all very well, but what would it do? It's not enough to say that > the syntax could exist, we also need to have semantics. What's the > use-case here? (That question is mostly aimed at the original poster.) Python could use parenthesis instead of brackets for indexing and a dictionary lookup. However it is too late to discuss this idea.
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