[Python-Dev] Overloading comparison operator for lists
Steven D'Aprano
steve at pearwood.info
Wed May 29 08:44:25 EDT 2019
More information about the Python-Dev mailing list
Wed May 29 08:44:25 EDT 2019
- Previous message (by thread): [Python-Dev] Overloading comparison operator for lists
- Next message (by thread): [Python-Dev] [PEP 558] thinking through locals() semantics
- Messages sorted by: [ date ] [ thread ] [ subject ] [ author ]
Hi Montana, As Cameron Simpson already pointed out, your query is off-topic for the Python-Dev mailing list and should be taken to the Python-Ideas mailing list, which is for speculative discussion of new designs. Like Cameron, I've CCed Python-Ideas. Please send any follow-ups to that list and not Python-Dev. You asked this question: On Tue, May 28, 2019 at 09:35:51PM -0600, Montana Burr wrote: > Ok, now I'm mildly curious to knpw: > > What is the justification for causing list == 3 to evaluate to False, > besides the obvious "a list cannot equal a number"? I concur with Terry Reedy -- what more justification is needed? A list cannot equal a number, so the default behaviour ought to be to return False. What would you have the default behaviour be? People have already suggested that getting the numpy-style behaviour is simple with a list comprehension, but the other technique is to subclass list, override ``__eq__`` and give it the behaviour you want. -- Steven
- Previous message (by thread): [Python-Dev] Overloading comparison operator for lists
- Next message (by thread): [Python-Dev] [PEP 558] thinking through locals() semantics
- Messages sorted by: [ date ] [ thread ] [ subject ] [ author ]
More information about the Python-Dev mailing list