Masklinn masklinn at masklinn.net
Fri Mar 18 17:32:28 CET 2011

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On 2011-03-18, at 14:58 , Mike Graham wrote:
> 
> *Of course, here I am ignoring the possibility that TotallyOrdered**
> is implemented as an abstract base class and all the stdlib is
> registered with it appropriately. This is because I don't think that
> would be the right thing to do – TotallyOrdered isn't a meaningful
> abstract type.

Why wouldn't TotallyOrdered not be a meaningful abstract type? Especially when compared to Sized or Hashable?

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