thehaas at my-deja.com thehaas at my-deja.com
Thu Aug 24 23:59:49 EDT 2000

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In article <31575A892FF6D1118F5800600846864D5B105A at intrepid>,
  Simon Brunning <SBrunning at trisystems.co.uk> wrote:
> > From:    Matthew Schinckel [SMTP:matt at null.net]
> > What about using re:
> >
> > re.sub("\n$", '', str)
> >

Oh please, let's not make things complicated . . .

str = str[:-1]

Although you have to be sure that the last char is a \n, because it will
take off whatever the last char is.  Sorta like chop(str) in Perl.

Mike


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