Nth digit of PI
Roy Smith
roy at popmail.med.nyu.edu
Wed Jul 5 07:53:47 EDT 2000
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Wed Jul 5 07:53:47 EDT 2000
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Randall Hopper <aa8vb at yahoo.com> wrote: > Pi^2/8 = sum(n=1..inf, 1/(2n-1)^2) Interesting, I've never seen that one before. It's not a very efficient way to compute pi (I know, that's not what you were trying to do). A little experimentation shows that 1000 terms only gets you 4 significant digits correct, and 10,000 terms still only had 5! -- Roy Smith <roy at popmail.med.nyu.edu> New York University School of Medicine
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