lambda and if
Emile van Sebille
emile at fenx.com
Mon Jun 12 07:07:37 EDT 2000
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Mon Jun 12 07:07:37 EDT 2000
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You could use this: >>> filenames = map(lambda x:x[2] + "_" + x[0] + "_" + ["","big"][x[1]=="big"] + ".txt" ,items) Emile van Sebille emile at fenx.com ------------------- ----- Original Message ----- From: matt <matt at virtualspectator.com> To: <python-list at python.org> Sent: Monday, June 12, 2000 3:46 AM Subject: lambda and if > say you had the following > > filenames = map(lambda x:x[2] + "_" + x[0] + "_" + x[1] + ".txt" ,items) > > but really wanted > filenames = map(lambda x:x[2] + "_" + x[0] + "_" + (x[1] in ("big",) ? "big" : > "") + ".txt" ,items) > > where (x[1] in ('big',) ? "big" : "") is a pseudo c++_pyhton expression that I > want to implement ..... > > i.e. the result is to append "big" to the filename being created if it is the > 2nd element of item, otherwise don't append anything. > > regards > Matt > > -- > http://www.python.org/mailman/listinfo/python-list >
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