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Q? Calling nearest inherited method

Guido van Rossum guido at python.org
Thu May 18 11:09:25 EDT 2000 
Laurent POINTAL wrote:
> 
> On Wed, 17 May 2000 18:37:00 GMT, Guido van Rossum <guido at python.org>
> wrote:
> 
> >: There's a better way.  (I believe Jeremy Hylton first suggested this; he saw
> >: it as an idiom in another language:)
> >:
> >: class C(B):
> >:     super_doit = B.doit
> >:     def doit(self, arg):
> >:         self.super_doit(arg)
> >:
> >: This avoids the need to explicitly pass self.
> 
> Not sure its really better...
> 1) The lowest problem: you have to define it for each function in each
> class in the hierarchy to have a clean model.

Yes, but this adds to the documentation of the class.

> 2) The biggest problem, it can go into infinite recursion...
[details omitted]

Argh!  Good catch.  My suggestion: use a naming convention
where it's called B_doit instead of super_doit.  But this *does*
make it less elegant, and you now need to know the base class name...

-- 
--Guido van Rossum (home page: http://www.python.org/~guido/)
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