evaluating a string
Joal Heagney
s713221 at student.gu.edu.au
Wed Oct 18 04:01:13 EDT 2000
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Wed Oct 18 04:01:13 EDT 2000
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Joal Heagney wrote: > Matthew Dixon Cowles wrote: > > > On Tue, 17 Oct 2000 04:01:24 GMT, prakash.ojha at hope.edu > > <prakash.ojha at hope.edu> wrote: > > > > >I am new to Python and would like to know how can I evaluate a string > > >like "1+2*3/4" to give a numeric result. Is there any built in > > >function that will give me this result. Any help would be greatly > > >appreciated. > > > > Since this is Python, the answer won't surprise you: the builtin > > eval() will do what you want: > > > > >>> eval("1+2*3/4") > > 2 > > > > Anticipating what may be your next question, the reason that it > > doesn't give you 2.5 is that in Python, division of integers produces > > an integer result. > > > > Regards, > > Matt > > And the quick way to get around that problem *showing of here*: > > >>> eval("%s""1+2*3/4" 1.0) > > *grins* > > Joal Heagney/AncientHart Hmm. Well that was wierd. It kinda worked on something similar, but when I tried it on the above string to check *shrugs*. This one works, but I don't think it will work all the time: >>> eval("1+2*3/4"".0") Perhaps a regular expression??? Joal Heagney/AncientHart
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