Newbie xml.sax question
Martin von Loewis
loewis at informatik.hu-berlin.de
Thu Jun 21 14:11:07 EDT 2001
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Thu Jun 21 14:11:07 EDT 2001
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gustafl at algonet.se (Gustaf Liljegren) writes: > class Parameters(saxutils.DefaultHandler): > def __init__(self, element, attribute): > self.element = element > self.attribute = attribute > def startElement(self, name, attrs): > if name == self.element: > return attrs.getValue(self.attribute) You shouldn't return a result from startElement; instead, you need to store the value for until after parsing, e.g. self.value = attrs[self.attribute] > from xml.sax import make_parser > parser = make_parser() > dh = Parameters('limits', 'max-depth') > parser.setContentHandler(dh) > print parser.parse('e:/test/config.xml') > > Now what? There's no error, but I can't figure out how to acctually > retrieve the value that the startElement method returns. The output from > the last line is None. Parsing does not return anything. If you've recorded the results, you can do parser.parse(...) print dh.value Regards, Martin
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