Roman Suzi rnd at onego.ru
Mon Jun 18 11:25:17 EDT 2001

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On Mon, 18 Jun 2001, Graham Ashton wrote:

> In article <u3d8x295d.fsf at cs.uu.nl>, "Unknown" <piet at cs.uu.nl> wrote:
> 
> > That is, if I understand how you want to do it:
> >         The list of functions is [f0, f1, f2] and you want: f0(tup[0])
> >         f1(tup[1])
> >         f2(tup[2])
> > 
> > You could do something like:
> > funlist = (self.column1, self.column2, self.some_column)
> > 
> > for i in range (len(funlist)):
> >         apply(funlist[i],(tup[i],))

map(lambda f, x: apply(f, (x,)), funlist, tup)

does the same, BTW.

Or even:

[apply(f, (x,)) for (f, x) in map(None, funlist, tup)]



Sincerely yours, Roman A.Suzi
-- 
 - Petrozavodsk - Karelia - Russia - mailto:rnd at onego.ru -
 

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