Question on if, while, for.... Figured it out..
Paul Rubin
phr-n2002a at nightsong.com
Mon Feb 11 17:42:23 EST 2002
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Mon Feb 11 17:42:23 EST 2002
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c at tech.usd253.org (Fred) writes: > if num > den: #Test for improper fraction. > i = num/den #This will only return the whole part. > j = num%den #This will return only the remainder. > > if j != 0: > for i in range(9,0,-1): > if num%i == 0 and den%i ==0 and test != 1: > a = j/i > b = den/i > print "You entered an improper fraction, simplified it > is: %d %d/%d" % (i,a,b), > test = 1 > else:... Does this do what you really want, if the fraction entered is 8/12?
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