sorting list of tuples by second (third...) tuple item
Paul Rubin
phr-n2002a at nightsong.com
Fri Feb 15 01:44:05 EST 2002
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Fri Feb 15 01:44:05 EST 2002
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kp87 at lycos.com (kevin parks) writes: > How would you sort something based on 2 criteria. Say you have a list > of lists (i hate tuples). first thing you want is everything sorted by > the first value and then everything that has the same value for [0] > then sorted by [1] # try this: yourlist = [['i3', 24.0, 0.5, 101, 7, 6, 7, 0, 0, 0, -1, 0, 5], \ ['i8', 82.25, 0.75, 101, 7, 6, 5, 0, 0, 0, 0, 0.02, 2], \ ['i9', 9, 0, 255], \ ['i8', 83.0, 1.0, 101, 1, 1, 5, 0, 0, 0, 0, 0.02, 2]] def compare_lists(x,y): a = cmp(x[0],y[0]) if a: return a return cmp(x[1],y[1]) yourlist.sort(compare_lists)
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