comparing nan "number"
Georgy Pruss
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Mon Dec 1 08:37:40 EST 2003
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Mon Dec 1 08:37:40 EST 2003
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"Boštjan Jerko" <bostjan.jerko at mf.uni-lj.si> wrote in message news:mailman.1215.1070277937.702.python-list at python.org... > Hello ! > > I need to know if the result of math formula is nan (Not a number). > How can I do that? > > Thanks, > > B. I used repr() as a workaround: >>> INF = 1e9999 >>> NAN = INF - INF >>> def isnan( x ): ... rx = repr(float(x)) ... return rx==repr(NAN) or rx==repr(-NAN) ... >>> t = 2*NAN >>> t == NAN False >>> t is NAN False >>> isnan(t) True You can also use binary representation of numbers: >>> import struct >>> NAN_POS = struct.pack('d',NAN) >>> NAN_NEG = struct.pack('d',-NAN) >>> def isnan2( x ): ... xs = struct.pack('d',float(x)) ... return xs==NAN_POS or xs==NAN_NEG ... HTH -- Georgy Pruss E^mail: 'ZDAwMTEyMHQwMzMwQGhvdG1haWwuY29t\n'.decode('base64')
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