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sismex01 at hebmex.com sismex01 at hebmex.com
Fri Jun 6 09:46:35 EDT 2003 
> From: Leeds, Mark [mailto:mleeds at mlp.com]
> Sent: Thursday, June 05, 2003 6:12 PM
> 
> I have another date question :
> 
> Now I have dates that are of the form
> 
> 2/14/1980 so
> I tried to read them in using
> 
> Temptime = time.strptime(filedate,"%m" + "//" + "%d" + "//" + 
> "%Y") But
> I get some weird error like format mismatch.
> 
> Could it be because the date is 2/14 instead of 02/14 ?
> 
> This will be my last question about dates.
> 
> 					mark
>

You *could* use a regular expression to reformat the date,
something like this:


Python 2.2 (#28, Dec 21 2001, 12:21:22) [MSC 32 bit (Intel)] on win32
Type "copyright", "credits" or "license" for more information.
IDLE 0.8 -- press F1 for help
>>> import re
>>> rxDate = re.compile(r"(\d{1,2})/(\d{1,2})/(\d{4})")
>>> def ReformatDate(dateString):
	date = rxDate.search(dateString)
	if date:
		return "%02d/%02d/%04d" % tuple(map(int,date.groups()))
	raise ValueError("Date has inappropriate format: %s" % dateString)

>>> ReformatDate("3/6/1969")
'03/06/1969'
>>>


hth.

-gca

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