incrementing a time tuple by one day
Donn Cave
donn at u.washington.edu
Thu Sep 23 15:06:31 EDT 2004
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Thu Sep 23 15:06:31 EDT 2004
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In article <QcudnRWf360rm87cRVn-vg at powergate.ca>, Peter Hansen <peter at engcorp.com> wrote: > David Stockwell wrote: > > I'm sure this has been asked before, but I wasn't able to find it. > > > > First off I know u can't change a tuple but if I wanted to increment a > > time tuple by one day what is the standard method to do that? > > > > I've tried the obvious things and haven't gotten very far. > > > > I have a time tuple that was created like this: > > aDate = '19920228' > > x = time.strptime(aDate,"%Y%m%d") > > print x > > (1992, 2, 28, 0, 0, 0, 4, 59, -1) > > > > y = time.mktime(x) + time.mktime((0,0,1,0,0,0,0,0,0)) > > print y > > 1643277600.0 > > print time.ctime(y) > > 'Thu Jan 27 05:00:00 2022' > > > > It appears to have decremented by a day and a month instead of increment. > > > > What am I doing wrong? > > What you're doing wrong is: not using the datetime module... > > >>> aDate = '19920228' > >>> x = time.strptime(aDate, '%Y%m%d') > >>> print x > (1992, 2, 28, 0, 0, 0, 4, 59, -1) > >>> d = datetime.datetime.fromtimestamp(time.mktime(x)) > >>> d > datetime.datetime(1992, 2, 28, 0, 0) > >>> y = d + datetime.timedelta(days=1) > >>> y.ctime() > 'Sat Feb 29 00:00:00 1992' $ python Python 2.2 (#1, 11/12/02, 23:31:59) [GCC Apple cpp-precomp 6.14] on darwin Type "help", "copyright", "credits" or "license" for more information. >>> import datetime Traceback (most recent call last): File "<stdin>", line 1, in ? ImportError: No module named datetime >>> Well, who knows, maybe datetime is the answer for him, but if not, I would just use 24*60*60 instead of trying to get one day in seconds out of mktime(). (I think if you look at the date closer, it isn't decremented all!) Donn Cave, donn at u.washington.edu
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