Adding through recursion
Gerard Flanagan
grflanagan at yahoo.co.uk
Fri Nov 18 09:39:10 EST 2005
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Fri Nov 18 09:39:10 EST 2005
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martin.clausen at gmail.com wrote: > I still don't get it. I tried to test with x = 0 and found that to > work. How come since the value of y is right and it is printed right it > "turns into" None when returned by the return statement ? Martin, -a function should either return something or not. Your function has two exit points, one explicitly returns a value, one doesn't (and so defaults to returning None). - trace through the function with pencil and paper for small values of x and y def add(x, y): if x: x -= 1 y += 1 add(x,y) else: print y def ADD(x, y): if x: x -= 1 y += 1 return ADD(x,y) else: return y >>>add(5,6) 11 >>>ADD(5,6) 11 >>>z = add(5,6) 11 >>>print z None >>>z = ADD(5,6) >>>print z 11 Gerard
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