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Mon Oct 17 07:08:56 EDT 2005

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oops, sorry. I meant

l1=[(date,v1,v2,v3), ...]
l2=[ another set of tuples ]


Thanks. so I have to concat the multiple lists first(all of them are
sorted already) ?

Alex Martelli wrote:
> I'm not sure what "my list is a tuple" mean (list and tuple being
> different types) nor what this has to do with the recipe.  Anyway...
> sequences are compared lexicographically -- first items first, then
> second items if the first items are equal, and so on.  So, if you have a
> list X whose items tuples and want X sorted on the tuples' first items,
> X.sort() will suffice -- if the tuples never have equal first-items, or
> if you're OK with second-items getting compared when the first-items are
> equal.  If you want to sort on first-items ONLY, leaving the tuples in
> the same order in the list when their first-items are equal:
> 
> import operator
> X.sort(key=operator.itemgetter(0))
> 
> 
> Alex

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