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Problem with variables assigned to variables???

M.-A. Lemburg mal at egenix.com
Wed Apr 30 06:18:36 EDT 2008 
On 2008-04-30 07:25, grepla at gmail.com wrote:
> I have a simple line of code that requires the following inputs - an
> input file, output file and a SQL expression.  the code needs to be
> run with several different SQL expressions to produce multiple output
> files.  To do this I first created a list of a portion of the output
> filename:
> mylist = ('name1', 'name2', 'name3')
> 
> I also assigned variables for each SQL expression:
> name1 = "\"field_a\" LIKE '021'"
> name2 = "\"field_a\" LIKE '031'"
> name3 = "\"field_a\" LIKE '041'"
> 
> Notice the variable names are the same as the listmember strings, that
> is intentional, but obviously doesn't work.
> 
> the loop:
> for listmember in mylist:
>     print listmember + ".shp", listmember
> 
> my intended output is:
> name1.shp "field_a LIKE '021'
> name2.shp "field_a LIKE '031'
> name3.shp "field_a LIKE '041'
> 
> but, of course, the variable listmember returns the name of the
> listmember which makes perfect sense to me:
> name1.shp name1
> 
> So how can I iterate not only the filenames but the SQL expressions as
> well?

The Python way to do this would be to take two lists, one
with the filenames and one with the SQL, and then iterate
over them in parallel:

for filename, sql_snippet in zip(filenames, sql_snippets):
     ...

(there are also a couple of ways to use iterators to do the
same)

If you just want to get you code to work, use this:

for listmember in mylist:
     print listmember + ".shp", locals()[listmember]


-- 
Marc-Andre Lemburg
eGenix.com

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