how to do draw pattern with python?
Hans Mulder
hansmu at xs4all.nl
Sat Sep 22 15:34:58 EDT 2012
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Sat Sep 22 15:34:58 EDT 2012
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On 21/09/12 19:32:20, Ian Kelly wrote: > On Fri, Sep 21, 2012 at 10:50 AM, Ismael Farfán <sulfurfff at gmail.com> wrote: >> 2012/9/21 Peter Otten <__peter__ at web.de>: >>> echo.hping at gmail.com wrote: >>> >>> print "\x1b[2J\x1b[0;0H" # optional >> >> Nice code : ) >> >> Could you dissect that weird string for us? >> >> It isn't returning the cursor to (0,0), it's just like executing >> clear(1), and looks like those line coloring scape sequences for bash. > > They're called "ANSI escape codes". :-) > > CSI 2J clears the screen. > CSI 0;0H means "move the cursor to row 0, column 0". However, I don't > think that's valid ANSI, as the coordinates are 1-based. Probably it > should have been "\x1b[2J\x1b[1;1H". Yes, the coordinates are 1-base, so it should have been "\x1b[2J\x1b[1;1H". Or, since 1;1 is the default, "\x1b[2J\x1b[H". On my machine, clear(1) uses "\x1b[H\x1b[2J". Using clear(1) appears to be the most portable way to do it: import os, time data = """\ x....x .x..x. ..xx.. ..xx.. .x..x. x....x """.splitlines() data = [line * 12 for line in data] # optional try: while True: os.system("clear") # optional for i, line in enumerate(data): print line data[i] = line[1:] + line[:1] time.sleep(.1) except KeyboardInterrupt: pass Hope this helps, -- HansM
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