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dict turn to list unexpected at runtime???

Cameron Simpson cs at zip.com.au
Fri Dec 5 02:19:45 EST 2014 
On 05Dec2014 15:01, telnetgmike at gmail.com <telnetgmike at gmail.com> wrote:
>Why the following code gives me errors??? And why the print statement run 2 times? I'll be appreciated your helps, thanks,
>addrnum_dict = {'a':1,'b':2}
>def orderaddrtimes():
>    global addrnum_dict
>    print type(addrnum_dict)
>
>    addrnum_dict = sorted(addrnum_dict.iteritems(), key=lambda d:d[1], reverse = True)

Because of the line above. The return value of "sorted()" is a list. You assign 
that list to "addrnum_dict". That name now refers to the list from "sorted()".

Because you call the orderaddrtimes() function twice, the second time you call 
it "addrnum_dict" is the list from the first call. Not a dict.

You would be best to not assign the result of "sorte()" to "addrnum_dict".  
Assign it to something else.

>    #addrnum_dict = OrderedDict(sorted(addrnum_dict.items(), key=lambda t: t[0]))
>if __name__ == '__main__':
>    kinds = ["a","b"]
>    for tmp_kind in kinds:
>        orderaddrtimes()
>
>######################
>errors:
>python aaa.py
><type 'dict'>
><type 'list'>
>Traceback (most recent call last):
>  File "aaa.py", line 16, in <module>
>    orderaddrtimes()
>  File "aaa.py", line 11, in orderaddrtimes
>    addrnum_dict = sorted(addrnum_dict.iteritems(), key=lambda d:d[1], reverse = True)
>AttributeError: 'list' object has no attribute 'iteritems'

Thank you for including the complete error output. This is very helpful, and 
often essential.

Cheers,
Cameron Simpson <cs at zip.com.au>

Who are all you people and why are you in my computer?  - Kibo
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