pad binary string with a given byte value (python 3)
Nagy László Zsolt
gandalf at shopzeus.com
Sat Sep 20 08:31:17 EDT 2014
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Sat Sep 20 08:31:17 EDT 2014
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>> bytes/str.ljust() >> >>>>> def pad(b, n=16, c=b"\x0f"): >> ... length = (len(b)+n-1)//n*n >> ... return b.ljust(length, c) > Thanks! One more question. How do I create a single char binary string from a number? E.g. >>> bytes([65]) b'A' It seems to be wrong again. The bytes constructor requires a sequence, and I don't like creating a list or a tuple just to convert it into a binary string. -- This message has been scanned for viruses and dangerous content by MailScanner, and is believed to be clean.
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