reshape and keep x,y,z ordering
Michael Selik
michael.selik at gmail.com
Tue Jun 7 09:16:37 EDT 2016
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Tue Jun 7 09:16:37 EDT 2016
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On Tue, Jun 7, 2016 at 7:31 AM Heli <hemla21 at gmail.com> wrote: > Hello, > I have a question regarding reshaping numpy array. > > I either have a 1D array that I need to reshape to a 3D array or a 3D > array to reshape to a 1d numpy array. > > In both of these cases it is assumed that data follows x,y,z ordering. > and I use the following to reshape the numpy array. > > new_1d_array=np.reshape(3d.transpose(),(3d_nx*3d_ny*3d_nz,)) > > new_3d_array=np.reshape(1d,((3d_x,3d_y,3d_z)).transpose()) > > My question is if there is anyway that reshape would keep x,y,z ordering > that would not require transpose? and if there is a better more efficient > way to do this? >>> a = np.arange(9).reshape(3,3) >>> a array([[0, 1, 2], [3, 4, 5], [6, 7, 8]]) >>> a.flatten() array([0, 1, 2, 3, 4, 5, 6, 7, 8]) >>> a.flatten('F') array([0, 3, 6, 1, 4, 7, 2, 5, 8]) Does this work for you? The flatten method normally goes row by row, but you can specify FORTRAN style column by column flattening.
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