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Sat Mar 26 21:46:08 EDT 2016

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Given that Python, like Ruby, is an object-oriented language why doesn't 
this:

def m():
   a = []
   for i in range(3): a.append(lambda: i)
   return a

b = m()
for n in range(3): print(b[n]())  # =>  2  2  2

... work the same as this in Ruby:

def m
   a = []
   (0..2).each {|i| a << ->(){i}}
   a
end

aa = m
(0..2).each {|n| puts aa[n].()}  # =>  0  1  2


lambda i=i: i

... is needed to make it work in Python. Just wondered why?

gvim

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