C++ vector::operator[] Function
The C++ vector::operator[] function is used to reference the element at the position specified inside the operator . The main distinction between operator[] function and the at() function is that the at() method throws an out-of-range exception when the location is outside the size of the vector, whereas this operator results in undefinable behavior. The time complexity of the operator[] function is constant.
Syntax
Following is the syntax for C++ vector::operator[] Function −
reference operator[] (size_type n);const_reference operator[] (size_type n) const;
Parameters
n − It indicates the posiion of an element present in the container.
Example 1
Let's consider the following example, where we are going to use the opertor=() function.
#include <iostream>
#include <vector>
using namespace std;
int main(void) {
vector<int> myvector = {1, 2, 3, 4, 5};
for (int x = 0; x < myvector.size(); ++x)
cout << myvector[x] << endl;
return 0;
}
Output
When we compile and run the above program, this will produce the following result −
1 2 3 4 5
Example 2
Considering the another scenario, where we are going to take the string type.
#include<iostream>
#include<vector>
using namespace std;
int main(){
vector<string> myvector{"BMW","AUDI","RS7","DUCATI"};
for(int x=0; x<myvector.size(); x++)
cout<<myvector.operator[](x)<<" ";
return 0;
}
Output
On running the above program, it will produce the following result −
BMW AUDI RS7 DUCATI
Example 3
In the following example, we are going to use the push_back() function to insert the elements and applying the operator[].
#include <iostream>
#include <vector>
using namespace std;
int main(){
vector<string> cars;
cars.push_back("RS7");
cars.push_back("DUCATI");
cars.push_back("VERNA");
cars.push_back("CRUZE LT");
cout <<"Result : " << cars[2];
return 0;
}
Output
When we execute the above program, it will produce the following result −
Result : VERNA
Example 4
Following is the example, where we are going to print the position of the element that is not divisible by 2.
#include <iostream>
#include <vector>
using namespace std;
int main(){
vector<int> mytutorial;
mytutorial.push_back(1);
mytutorial.push_back(2);
mytutorial.push_back(3);
mytutorial.push_back(4);
mytutorial.push_back(5);
mytutorial.push_back(6);
mytutorial.push_back(7);
for (int i = 0; i < mytutorial.size(); ++i) {
if (i % 2 != 0) {
cout << mytutorial[i];
cout << " ";
}
}
return 0;
}
Output
On running the above program, it will produce the following result −
2 4 6