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Problem Description

How to use catch to handle the exception?

Solution

This example shows how to use catch to handle the exception.

public class Main{
   public static void main (String args[]) {
      int array[] = {20,20,40};
      int num1 = 15, num2 = 10;
      int result = 10;
      try {
         result = num1/num2;
         System.out.println("The result is" +result);
         
         for(int i = 5; i >= 0; i--) {
            System.out.println("The value of array is" +array[i]);
         }
      } catch (Exception e) {
         System.out.println("Exception occoured : "+e);
      }
   }
}

Result

The above code sample will produce the following result.

The result is1
Exception occoured : java.lang.ArrayIndexOutOfBoundsException: 5

The following is an another example of catch to handle the exception in Java

public class Trycatch { 
   public static void main(String args[]) { 
      try { 
         int data = 50/0; 
      } catch(ArithmeticException e){System.out.println(e);}
      System.out.println("rest of the code...");
   }
}

The above code sample will produce the following result.

java.lang.ArithmeticException: / by zero
rest of the code...

java_exceptions.htm