Section 4.4 of the tutorial gives example code: 

>>> for n in range(2, 10):
...     for x in range(2, n):
...         if n % x == 0:
...             print n, 'equals', x, '*', n/x
...             break
...     else:
...         # loop fell through without finding a factor
...         print n, 'is a prime number'
... 
2 is a prime number
3 is a prime number
4 equals 2 * 2
5 is a prime number
6 equals 2 * 3
7 is a prime number
8 equals 2 * 4
9 equals 3 * 3

When one is to enter the code (print n, 'equals' x, '*' n/x) you are
given syntax error:   File "<stdin>", line 4
    print n, 'equals' x, '*' n/x
                      ^
SyntaxError: invalid syntax

In the example code from the tutorial you gave, there was still a comma
separator between the string 'equals' and the reference `x`. This is
missing when you entered the code, that's why Python is throwing an
exception there.

I made a type in that line, but when the typo isn't there I get the same
thing. It turns out that it was an error from running a slightly older
version of the dev kit. Now that I have updated the dev kit it runs, but
I end up with the following as an output:

3 is a prime number
4 equals 2 * 2
5 is a prime number
5 is a prime number
5 is a prime number
6 equals 2 * 3
7 is a prime number
7 is a prime number
7 is a prime number
7 is a prime number
7 is a prime number
8 equals 2 * 4
9 is a prime number
9 equals 3 * 3

as opposed to the desired

2 is a prime number
3 is a prime number
4 equals 2 * 2
5 is a prime number
6 equals 2 * 3
7 is a prime number
8 equals 2 * 4
9 equals 3 * 3

Sorry, but there must be another typo in your code.
I guess the else clause isn't correctly indented -- it belongs to the
"for" statement, not the "if" statement.

@Georg: you were correct, the indentation was incorrect, I suggest that
there be some additional notation be added to code examples in the
documentation showing how many tabs there are, to make for an easier
read and minimize on errors.