When trying to print a type in a formatted string with padding TypeError is raised. See examples below.

These work:
>>> a = 'abc'
>>> print('{a}'.format(a=type(a)))
<class 'str'>
>>> print('{a}'.format(a=str(type(a))))
<class 'str'>

These don't:
>>> print('{a: >10}'.format(a=type(a)))
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: unsupported format string passed to type.__format__
>>> t = type(a)
>>> print('{a: >10}'.format(a=t))
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: unsupported format string passed to type.__format__

`type` has a default `__format__` implementation which doesn't accept any formatting options. This is expected behaviour.

The problem is that type.__format__ doesn't exist, so object.__format__ is being called, and it throws an error if you provide a format spec. This is done for future expansion: if we do want to add type.__format__ in the future, we don't have to worry about existing cases that are using format specs that might not work with the new type.__format__.

No format spec is the same as calling str() on the argument and returning that, which is what is happening in your working examples.

If you want to apply a str formatting spec, you should covert the argument to a str first, using either !s or str():

>>> print('{a!s: >10}'.format(a=type(a)))
<class 'str'>
>>> print('{a: >10}'.format(a=str(type(a))))
<class 'str'>

nosy: + abarry
messages: + msg316074

resolution: not a bug
stage: resolved