Issue 36349: Including parentheses in a regular expression pattern enclosed by literal square bracket characters cause the square brackets not to be matched

Issue36349

Created on 2019-03-18 15:03 by Farbod Safe2, last changed 2022-04-11 14:59 by admin. This issue is now closed.

Messages (4)
msg338234 - (view)	Author: Farbod Safe (Farbod Safe2)	Date: 2019-03-18 15:03
Below two print statements should give the same results but they don't: import re s = '[a]' print(re.findall(r'\[.]',s)) [a] print(re.findall(r'\[(.)]',s)) a
msg338236 - (view)	Author: Stéphane Wirtel (matrixise) *	Date: 2019-03-18 15:07
3.6 is in security mode and not in bugfix mode. Please, use 3.7.
msg338237 - (view)	Author: Stéphane Wirtel (matrixise) *	Date: 2019-03-18 15:07
Python 3.7.2 (default, Jan 16 2019, 19:49:22) [GCC 8.2.1 20181215 (Red Hat 8.2.1-6)] on linux Type "help", "copyright", "credits" or "license" for more information. >>> import re >>> s = '[a]' >>> print(re.findall(r'\[.]', s)) [a] >>> print(re.findall(r'\[.]', s)) [a] >>>
msg338239 - (view)	Author: SilentGhost (SilentGhost) *	Date: 2019-03-18 15:19
Fabrod, this has nothing to do with the square brackets. It is your assumption that the return value should be the same that is wrong. Cf.: >>> re.findall(r'a.+', 'abc') ['abc'] >>> re.findall(r'a(.+)', 'abc') ['bc'] This is the correct documented behaviour.

History
Date	User	Action	Args
2022-04-11 14:59:12	admin	set	github: 80530
2019-03-18 15:19:52	SilentGhost	set	resolution: out of date -> not a bug messages: + msg338239 nosy: + SilentGhost
2019-03-18 15:07:34	matrixise	set	messages: + msg338237
2019-03-18 15:07:15	matrixise	set	status: open -> closed nosy: + matrixise messages: + msg338236 resolution: out of date stage: resolved
2019-03-18 15:03:59	Farbod Safe2	create