This article was created to cover some programs in Python that count the total number of digits in a given number. Here is a list of programs created for this article:

• Count digits in a number using the "while" loop.
• Count digits in a number using the "len()" function.

For example, if the user inputs a number like "4298", then the output will be "4" because the number contains 4 digits.

Count the total digits in a number using a while loop

The question is: write a Python program to count the total digits available in a given number using a while loop. The program given below is the answer to this question:

print("Enter the Number: ")
num = int(input())
tot = 0

while num:
  num = int(num/10)
  tot = tot+1

print("\nTotal Digit: ")
print(tot)

Here is its sample run:

Now supply the input "10324" as a number and press the ENTER key to count and print the total number of digits available in the given number, as shown in the snapshot given below:

Modified Version of the Previous Program

This program uses "end", which skips the insertion of an automatic newline. "str()" converts any type of value to a string type.

print(end="Enter the Number: ")
num = int(input())
tot = 0

while num:
  num = int(num/10)
  tot = tot+1

if tot>1:
  print("\nThere are " +str(tot)+ " digits available in the number")
elif tot==1:
  print("\nIt is a single digit number")

Here is its sample run with user input, "12340":

Count Digits using len()

This program uses a predefined function named "len()" to count digits in a given number.

print(end="Enter the Number: ")
num = int(input())

num = str(num)
numLen = len(num)

print("\nTotal Digit: " + str(numLen))

Here is its sample run with user input, "401":

Python Online Test

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