Python reversed() Function
The reversed() function in Python returns the reversed iterator object or the iterator of a given sequence such as list, tuple, string etc. For example:
a = [32, 34, 56, 76] b = reversed(a) for x in b: print(x, end=" ")
Following is the output produced by this Python program, demonstrating the reversed() function:
Python reversed() Function Syntax
The syntax of reversed() function is:
Python reversed() Function Example
Here is an example example that uses the reversed() function to get the reverse iterator of a sequence:
print("Enter the size: ", end="") n = int(input()) print("Enter", n, "elements: ", end="") seq = [] for i in range(n): val = input() seq.append(val) print("\nThe original sequence is:") for x in seq: print(x, end=" ") seq = reversed(seq) print("\nThe reversed sequence is:") for x in seq: print(x, end=" ")
The snapshot given below shows the sample run of above program, with user input 5 as size, and 50, 60, 70, 80, 90 as five numbers for the sequence:
Important - The list_reverseiterator object is not subscriptable. Therefore, we can not access the element through indexing. If we do so, like shown in the program given below:
seq = [12, 23, 34, 45] n = 4 print("The original sequence is:") for i in range(n): print(seq[i], end=" ") seq = reversed(seq) print("\nThe reversed sequence is:") for i in range(n): print(seq[i], end=" ")
Then it will raised the error like shown in the snapshot given below. This snapshot is taken from the output produced by above program:
Therefore we need to replace the following block of code from above program:
for i in range(n): print(seq[i], end=" ")
with the block of code given below:
for x in seq: print(x, end=" ")
If you create a program like:
seq = [12, 23, 34, 45] print(reversed(seq))
then the output you'll see, looks similar to:
<list_reverseiterator object at 0x000001E89AF18040>
which is not the output that we need. Because we need the same sequence, but in reverse. Therefore we need to wrap the reversed() inside a list. Here is the modified version of previous program:
seq = [12, 23, 34, 45] print(list(reversed(seq)))
Now the output would be:
Here is another example uses reversed() function to get the reversed iterator object of a sequence.
mystring = "codescracker" print(list(reversed(mystring))) mylist = [1, 2, 3] print(list(reversed(mylist))) mytuple = (4, 5, 6) print(list(reversed(mytuple))) myrange = range(10) print(list(reversed(myrange)))
The output produced by this program will exactly be:
['r', 'e', 'k', 'c', 'a', 'r, 'c', 's', 'e', 'd', 'o', 'c'] [3, 2, 1] [6, 5, 4] [9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
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