A simple, generic implementation of Binary Trees in Go.
Installation
Install go-binarytree by executing the following command.
go get -v gopkg.in/dnaeon/go-binarytree.v1
Usage
The following example builds a simple binary tree with 7 nodes, and performs in-, pre-, post- and level-order walking of the tree (error handling is omitted for simplicity).
package main import ( "fmt" "gopkg.in/dnaeon/go-binarytree.v1" ) func main() { root := binarytree.NewNode(10) five := root.InsertLeft(5) twenty := root.InsertRight(20) five.InsertLeft(9) five.InsertRight(18) twenty.InsertLeft(3) twenty.InsertRight(7) fmt.Printf("height of tree: %d\n", root.Height()) fmt.Printf("size of the tree: %d\n", root.Size()) fmt.Printf("tree is balanced: %t\n", root.IsBalancedTree()) fmt.Printf("tree is complete: %t\n", root.IsCompleteTree()) fmt.Printf("tree is perfect: %t\n", root.IsPerfectTree()) // Function to be called while walking the tree, which simply // prints the values of each visited node walkFunc := func(n *binarytree.Node[int]) error { fmt.Printf("%d ", n.Value) return nil } fmt.Printf("in-order values: ") root.WalkInOrder(walkFunc) fmt.Println() fmt.Printf("pre-order values: ") root.WalkPreOrder(walkFunc) fmt.Println() fmt.Printf("post-orer values: ") root.WalkPostOrder(walkFunc) fmt.Println() fmt.Printf("level-order values: ") root.WalkLevelOrder(walkFunc) fmt.Println() }
Running above example produces the following output.
height of tree: 2 size of the tree: 7 tree is balanced: true tree is complete: true tree is perfect: true in-order values: 9 5 18 10 3 20 7 pre-order values: 10 5 9 18 20 3 7 post-orer values: 9 18 5 3 7 20 10 level-order values: 10 5 20 9 18 3 7
The following example generates the Dot representation of the binary tree and prints it to the standard output.
package main import ( "os" "gopkg.in/dnaeon/go-binarytree.v1" ) func main() { root := binarytree.NewNode(10) five := root.InsertLeft(5) twenty := root.InsertRight(20) five.InsertLeft(9) five.InsertRight(18) twenty.InsertLeft(3) twenty.InsertRight(7) root.WriteDot(os.Stdout) }
Running above example produces an output similar to this one.
digraph {
node [color=lightblue fillcolor=lightblue fontcolor=black shape=record style="filled, rounded"]
824634441792 [label="<l>|<v> 10|<r>" ]
824634441792:l -> 824634441856:v
824634441792:r -> 824634441920:v
824634441856 [label="<l>|<v> 5|<r>" ]
824634441856:l -> 824634441984:v
824634441856:r -> 824634442048:v
824634441984 [label="<l>|<v> 9|<r>" ]
824634442048 [label="<l>|<v> 18|<r>" ]
824634441920 [label="<l>|<v> 20|<r>" ]
824634441920:l -> 824634442112:v
824634441920:r -> 824634442176:v
824634442112 [label="<l>|<v> 3|<r>" ]
824634442176 [label="<l>|<v> 7|<r>" ]
}The generated representation can be rendered using graphviz, e.g.
dot -Tsvg /path/to/file.dot -o /tmp/to/file.svg
When building a binary tree with user-defined types such as structs, make sure that you also implement the fmt.Stringer interface for your type, so that Dot generation works properly.
Make sure to check the included test cases for additional examples.
Tests
Run the tests.
License
go-binarytree is Open Source and licensed under the BSD
License.