[3.7] bpo-33264 Remove to-be-deprecated urllib.request.urlretrieve function reference (GH-6454) by miss-islington · Pull Request #6486 · python/cpython
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@@ -56,12 +56,20 @@ The simplest way to use urllib.request is as follows::
with urllib.request.urlopen('http://python.org/') as response:
html = response.read()
If you wish to retrieve a resource via URL and store it in a temporary location, you can do so via the :func:`~urllib.request.urlretrieve` function:: If you wish to retrieve a resource via URL and store it in a temporary location, you can do so via the :func:`shutil.copyfileobj` and :func:`tempfile.NamedTemporaryFile` functions::
import shutil import tempfile import urllib.request local_filename, headers = urllib.request.urlretrieve('http://python.org/') html = open(local_filename)
with urllib.request.urlopen('http://python.org/') as response: with tempfile.NamedTemporaryFile(delete=False) as tmp_file: shutil.copyfileobj(response, tmp_file)
with open(tmp_file.name) as html: pass
Many uses of urllib will be that simple (note that instead of an 'http:' URL we could have used a URL starting with 'ftp:', 'file:', etc.). However, it's the Expand Down
If you wish to retrieve a resource via URL and store it in a temporary location, you can do so via the :func:`~urllib.request.urlretrieve` function:: If you wish to retrieve a resource via URL and store it in a temporary location, you can do so via the :func:`shutil.copyfileobj` and :func:`tempfile.NamedTemporaryFile` functions::
import shutil import tempfile import urllib.request local_filename, headers = urllib.request.urlretrieve('http://python.org/') html = open(local_filename)
with urllib.request.urlopen('http://python.org/') as response: with tempfile.NamedTemporaryFile(delete=False) as tmp_file: shutil.copyfileobj(response, tmp_file)
with open(tmp_file.name) as html: pass
Many uses of urllib will be that simple (note that instead of an 'http:' URL we could have used a URL starting with 'ftp:', 'file:', etc.). However, it's the Expand Down