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tkinter call backs

Gordon Williams g_will at cyberus.ca
Mon Jul 19 13:40:43 EDT 1999 
Hi,

In fileopen(), root is a unknown name because (I believe) I dont pass root
to it.  Fileopen() is a call back (and I dont know how to pass an instance
or variable through a call back).  I get an name error when I then use

fileName=tkFileDialog.askopenfilename(parent=root, title="Open")

This part is in a module to make a menu.  When the module is tested by
itself it runs fine and root does not give and error.  print root returns .
(period).  When the module is imported into the main module and then used,
I now get an error.  root=Tk() is defined in the main module.  Is this a
problem of local and global names?  How do I overcome it?




Fredrik Lundh <fredrik at pythonware.com> wrote in article
<00ca01bed209$5543adf0$f29b12c2 at secret.pythonware.com>...
> Gordon Williams <g_will at cyberus.ca> wrote:
> > I have a simple problem that I cant find the solution.  I have a menu
item
> > to open a file which has a command "openfile".  I would like to
activate
> > "tkFileDialog.askopenfilename" to get the name of the file.  This
requires
> > "parent=root" or something like that for the position of the message
box.
> > 
> > How do I pass "root" into openfile?  
> 
> after which he promptly answered his own
> question:
> 
> >     fileName=tkFileDialog.askopenfilename(parent=root, title="Open")
> 
> what am I missing here?
> 
> </F>
> 
>
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