Fredrik Lundh fredrik at pythonware.com
Mon Jul 19 13:08:32 EDT 1999

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Gordon Williams <g_will at cyberus.ca> wrote:
> I have a simple problem that I cant find the solution.  I have a menu item
> to open a file which has a command "openfile".  I would like to activate
> "tkFileDialog.askopenfilename" to get the name of the file.  This requires
> "parent=root" or something like that for the position of the message box.
> 
> How do I pass "root" into openfile?  

after which he promptly answered his own
question:

>     fileName=tkFileDialog.askopenfilename(parent=root, title="Open")

what am I missing here?

</F>

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