In an integral domain , the decomposition of a nonzero noninvertible element
as a product of prime (or irreducible)
factors
|
(1) |
is unique if every other decomposition of the same type has the same number of factors
|
(2) |
and its factors can be rearranged in such a way that for all indices ,
and
differ by an invertible factor.
The prime factorization of an element, if it exists, is always unique, but this does not apply, in general, to irreducible factorizations: in the ring ,
|
(3) |
are two different irreducible factorizations, none of which is prime. 2 is not a prime element in ,
since it does not divide either of the factors of the middle expression. In fact
|
(4) |
lie both outside .
Furthermore,
|
(5) |
which shows that
is not prime either.
An integral domain where every nonzero noninvertible element admits a unique irreducible factorization is called a unique factorization domain.
See also
Fundamental Theorem of Arithmetic, Unique Factorization Domain
This entry contributed by Margherita Barile
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References
Sigler, L. E. Algebra. New York: Springer-Verlag, 1976.
Referenced on Wolfram|Alpha
Cite this as:
Barile, Margherita. "Unique Factorization." From MathWorld--A Wolfram Resource, created by Eric W. Weisstein. https://mathworld.wolfram.com/UniqueFactorization.html